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90=5x^2-15x
We move all terms to the left:
90-(5x^2-15x)=0
We get rid of parentheses
-5x^2+15x+90=0
a = -5; b = 15; c = +90;
Δ = b2-4ac
Δ = 152-4·(-5)·90
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-45}{2*-5}=\frac{-60}{-10} =+6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+45}{2*-5}=\frac{30}{-10} =-3 $
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